A steel spring stores 18 J of potential energy when it is stretched by 2.40 cm. Determine the spring constant of the spring in N/m.
Added by Ben F.
Step 1
In this case, we are given that the potential energy is 18 J and the displacement is 2.40 cm (or 0.024 m). Plugging these values into the formula, we get: 18 J = (1/2) * k * (0.024 m)^2 To solve for k, we can rearrange the equation: k = (2 * 18 J) / (0.024 Show more…
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