Question

A stone is tossed into the air from ground level with an initial velocity of 30 m/s. Its height at time $t$ is $h(t) = 30t - 4.9t^2$ m. Compute the stone's average velocity $\bar{v}$ in m/s over the time intervals $[3, 3.01]$, $[3, 3.001]$, $[3, 3.0001]$ and $[2.9999, 3]$, $[2.999, 3]$, $[2.99, 3]$.

          A stone is tossed into the air from ground level with an initial velocity of 30 m/s. Its height at time $t$ is $h(t) = 30t - 4.9t^2$ m.
Compute the stone's average velocity $\bar{v}$ in m/s over the time intervals $[3, 3.01]$, $[3, 3.001]$, $[3, 3.0001]$ and $[2.9999, 3]$, $[2.999, 3]$, $[2.99, 3]$.

A stone is tossed into the air from ground level with an initial velocity of 30 m/s. Its height at time t is h(t) = 30t - 4.9t^2 m.
Compute the stone's average velocity v̅ in m/s over the time intervals [3, 3.01], [3, 3.001], [3, 3.0001] and [2.9999, 3], [2.999, 3], [2.99, 3].

Added by Elaine P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Dishary Hossain

06/07/2019

Step 1

Step 1: To find the average velocity over a time interval, we can use the formula for average velocity: average velocity = (change in position) / (change in time) Show more…

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A stone is tossed into the air from ground level with an initial velocity of 30(m)/(s). Its height at time t is h(t)=30t-4.9t^(2)m. Compute the stone's average velocity /bar (v) in (m)/(s) over the time intervals 3,3.01 3,3.001 3,3.0001 and 2.9999,3 2.999,3, 2.99,3 A stone is tossed into the air from ground level with an initial velocity of 30 m/s. Its height at time t is h(t) = 30t -- 4.9t2 m. [2.99,3].