00:01
So for part a of this problem, it's important to remember that in studying the hall effect, that equilibrium is reached when the magnitude of the magnetic force and the moving charges is equal to the magnitude of the electrical force caused by the field which separates those charges.
00:20
And so in doing so, we can set the electric force, qe, equal to the magnetic force qv drift b, and then we can just solve for v drift as e over b.
00:38
And using the numbers from the problem here, we get a ultimate drift velocity of about six times 10 to the minus 4 meters per second.
00:57
And so now, moving on to part b, we can circle this here, moving on to part b, we have that there is an electron, an electron density of some number of electrons per cubic meter and a cross -sectional area of the strip.
01:16
Well, we can do some reasoning with some dimensional analysis to say that the current is therefore going to be equal to a charge times some velocity v.
01:28
Drift...