Question

A student adds 100.0 mL of a 0.35 M barium chloride solution and 80.0 mL of a 0.45 M sodium sulphate solution to a 500.0 mL beaker. Answer the following questions, do not round until the very end, and report your answer to 3 decimal places without units. a) What is the molar concentration of barium ions in the beaker? b) What is the molar concentration of chloride ions in the beaker? c) What is the molar concentration of sodium ions in the beaker? d) What is the molar concentration of sulphate ions in the beaker?

          A student adds 100.0 mL of a 0.35 M barium chloride solution and 80.0 mL of a 0.45 M sodium sulphate solution to a 500.0 mL beaker. Answer the following questions, do not round until the very end, and report your answer to 3 decimal places without units.
a) What is the molar concentration of barium ions in the beaker? 
b) What is the molar concentration of chloride ions in the beaker? 
c) What is the molar concentration of sodium ions in the beaker? 
d) What is the molar concentration of sulphate ions in the beaker?

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Added by Patrick W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

07/03/2023

Step 1

a) Moles of barium ions: moles = Molarity × Volume moles(Ba) = 0.35 M × 0.100 L = 0.035 mol b) Moles of chloride ions: Since there are 2 moles of chloride ions for every mole of barium chloride, we multiply the moles of barium ions by 2. moles(Cl) = 2 × 0.035 Show more…

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A student adds 100.0 mL of a 0.35 M barium chloride solution and 80.0 mL of a 0.45 M sodium sulphate solution to a 500.0 mL beaker. Answer the following questions, do not round until the very end, and report your answer to 3 decimal places without units. a) What is the molar concentration of barium ions in the beaker? b) What is the molar concentration of chloride ions in the beaker? c) What is the molar concentration of sodium ions in the beaker? d) What is the molar concentration of sulphate ions in the beaker?

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