00:01
The ph of the solution made by combining 150 ml of 0 .10 molar k -oh and 50ml of 0 .20 motor hbr is closest to 24 to a2b4c7d2.
00:31
We're going to find out how.
00:32
Okay, so this acid and the base when the react is a ratio of one -to -one, right? because you have a kbr pond and water.
00:48
So it's one -to -one.
00:51
Anyways, so what we're going to do is to say we want to know which one will be like excess.
01:01
So kind of looking at it, i'm suspecting that this potassiumide oxide is the excess.
01:06
So, but we can just take the hbr as the acid, right? and determine what volume of the base of this concentration will be required to react to it.
01:21
So all we're going to do is to say c -a, v -a over c -b -b is equal to n -a over n -b, where here is acid and b is base.
01:35
Alright, so let's do this.
01:38
So, c is concentration and v its volume, right? so c for hac, c, a, o 'e, 0 .10, multiply by va, which is 0 .20.
01:56
0 .20, multiply by va, which is 50, divided by cb, 0 .10, multiplied by vb, that's what i'll figure out, is 1 to 1.
02:08
So vb will be 0 .20 multiplied by 50, multiplied by 1, divided by 0 .10, multiplied by 1.
02:23
So 0 .2 times 50 divided by 0 .1...