00:01
In this question we are having a situation as for a building and our survey.
00:16
So according to the question, first of all, we will make a diagram.
00:20
So let's take this ab as a building and the survey is at this point here.
00:29
So the angle form in between the top of the building and the survey is theta.
00:35
So let's take our height as edge and the distance.
00:40
For the surveyor is 30 meters.
00:45
So now in the solution of the square few, first of all we will let here h be the height of the building.
01:03
So now if h is the height and here we can see this is a 90 degree angle so we can apply in frangles a bc angle b is equal to 90 so by using trigonmetic ratio of t theta 10 theta is equal to perpendicular upon base.
01:24
So therefore this will be as h .y.
01:28
30 and our value for 10, theta is now h by 30.
01:36
So therefore h will be equal to 30, 10 theta...