Stokes' Law is given by:
\[ v = \frac{2gr^2(\rho_p - \rho_f)}{9\mu} \]
where:
- \(v\) is the terminal velocity (m/s),
- \(g\) is the acceleration due to gravity (\(9.81 m/s^2\)),
- \(r\) is the radius of the particle (m),
- \(\rho_p\) is the density of the
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