Question

A system with an unperturbed Hamiltonian H_0 is subject to a perturbation H' with H_0 = E_0 egin{pmatrix} 15 & 0 & 0 & 0 \ 0 & 3 & 0 & 0 \ 0 & 0 & 3 & 0 \ 0 & 0 & 0 & 3 end{pmatrix}, and H' = alpha E_0 egin{pmatrix} 0 & 0 & 0 & 0 \ 0 & 0 & 1 & 0 \ 0 & 1 & 0 & 0 \ 0 & 0 & 0 & 0 end{pmatrix}. Where alpha is the strength of perturbation. 1. Find out the energy eigenvalues and eigenstates of the unperturbed Hamiltonian. 2. Write down the total Hamiltonian of the system in matrix form using H = H_0 + H'. 3. Find out the energy eigenvalues of the total Hamiltonian (H). 4. In calculating part (1) you will observe that H_0 has one nondegenerate eigenvalue and a threefold degenerate eigenvalues. Keeping this point in mind and just focusing the nondegenerate value of H_0 find the first-order correction in this specific energy. (Hint: E_n^1 = langle Psi_n^0 | H' | Psi_n^0 angle)

          A system with an unperturbed Hamiltonian H_0 is subject to a perturbation H' with
H_0 = E_0 egin{pmatrix} 15 & 0 & 0 & 0 \ 0 & 3 & 0 & 0 \ 0 & 0 & 3 & 0 \ 0 & 0 & 0 & 3 end{pmatrix}, and H' = alpha E_0 egin{pmatrix} 0 & 0 & 0 & 0 \ 0 & 0 & 1 & 0 \ 0 & 1 & 0 & 0 \ 0 & 0 & 0 & 0 end{pmatrix}.
Where alpha is the strength of perturbation.
1. Find out the energy eigenvalues and eigenstates of the unperturbed Hamiltonian.
2. Write down the total Hamiltonian of the system in matrix form using H = H_0 + H'.
3. Find out the energy eigenvalues of the total Hamiltonian (H).
4. In calculating part (1) you will observe that H_0 has one nondegenerate eigenvalue and a threefold degenerate eigenvalues. Keeping this point in mind and just focusing the nondegenerate value of H_0 find the first-order correction in this specific energy. (Hint: E_n^1 = langle Psi_n^0 | H' | Psi_n^0 
angle)
        
Show more…
A system with an unperturbed Hamiltonian H0 is subject to a perturbation H' with
H0 = E0 eginpmatrix 15     0     0     0  0     3     0     0  0     0     3     0  0     0     0     3 endpmatrix, and H' = alpha E0 eginpmatrix 0     0     0     0  0     0     1     0  0     1     0     0  0     0     0     0 endpmatrix.
Where alpha is the strength of perturbation.
1. Find out the energy eigenvalues and eigenstates of the unperturbed Hamiltonian.
2. Write down the total Hamiltonian of the system in matrix form using H = H0 + H'.
3. Find out the energy eigenvalues of the total Hamiltonian (H).
4. In calculating part (1) you will observe that H0 has one nondegenerate eigenvalue and a threefold degenerate eigenvalues. Keeping this point in mind and just focusing the nondegenerate value of H0 find the first-order correction in this specific energy. (Hint: En^1 = langle Psin^0 | H' | Psin^0 
angle)

Added by James B.

Close

Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
A system with an unperturbed Hamiltonian H0 is subject to a perturbation H' with H0 = E0 (15 0 0 0; 0 3 0 0; 0 0 3 0; 0 0 0 3), and H' = alpha E0 (0 0 0 0; 0 0 1 0; 0 1 0 0; 0 0 0 0). Where alpha is the strength of perturbation. 1. Find out the energy eigenvalues and eigenstates of the unperturbed Hamiltonian. 2. Write down the total Hamiltonian of the system in matrix form using H = H0 + H'. 3. Find out the energy eigenvalues of the total Hamiltonian (H). 4. In calculating part (1) you will observe that H0 has one nondegenerate eigenvalue and a threefold degenerate eigenvalues. Keeping this point in mind and just focusing the nondegenerate value of H0 find the first-order correction in this specific energy. (Hint: E_n^1 = <Psi_n^0| H' |Psi_n^0>)
Close icon
Play audio
Feedback
Powered by NumerAI
Danielle Fairburn David Collins
Jennifer Stoner verified

Sri K and 56 other subject Calculus 3 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Textbooks

-
Calculus: Early Transcendentals

Calculus: Early Transcendentals

James Stewart 8th Edition
achievement 1,599 solutions
Calculus: Early Transcendentals

Calculus: Early Transcendentals

William Briggs, Lyle Cochran, Bernard Gillet 3rd Edition
achievement 1,267 solutions
Thomas Calculus

Thomas Calculus

George B. Thomas Jr. 14th Edition
achievement 1,181 solutions

*

Transcript

-
00:01 In this question, we have been given an unpertured hamiltonian h -0, which is subjected to a perturbation h -d -s.
00:10 Okay, so h -0 is given to be e -0 times this matrix is 15 -0 -0 -0 -3 -0.
00:19 Then we have 0 -3 -0.
00:21 Then we have 0 -3, and lastly, we have 0 -0 -0 -3.
00:24 Okay.
00:26 And then we have been given h -daz, which is a perturbation.
00:30 Which is given to be alpha times of e not of this matrix 000 then we have 010 then 0100 and then lastly we have 0 0 0 0 okay so this is perturbed and unperturbed hamiltonian here alpha is the strength of hamiltonian perturbation sorry first of all what we have to find out in the first part we have to find out energy eigenvalues and eigenstate of the unperturbed hamiltonian.
01:01 So let us see how can we do this? so for unperturbed, which is denoted by h0 cap, the eigenstates, if i write down, the eigenstates are given by the 5 -1.
01:29 Okay, this is the first eigenstate, which will be 1 -0 -0...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever