00:01
In this question, we have been given an unpertured hamiltonian h -0, which is subjected to a perturbation h -d -s.
00:10
Okay, so h -0 is given to be e -0 times this matrix is 15 -0 -0 -0 -3 -0.
00:19
Then we have 0 -3 -0.
00:21
Then we have 0 -3, and lastly, we have 0 -0 -0 -3.
00:24
Okay.
00:26
And then we have been given h -daz, which is a perturbation.
00:30
Which is given to be alpha times of e not of this matrix 000 then we have 010 then 0100 and then lastly we have 0 0 0 0 okay so this is perturbed and unperturbed hamiltonian here alpha is the strength of hamiltonian perturbation sorry first of all what we have to find out in the first part we have to find out energy eigenvalues and eigenstate of the unperturbed hamiltonian.
01:01
So let us see how can we do this? so for unperturbed, which is denoted by h0 cap, the eigenstates, if i write down, the eigenstates are given by the 5 -1.
01:29
Okay, this is the first eigenstate, which will be 1 -0 -0...