00:01
It is given that a test for a disease gives a correct positive result with probability 0 .95 when the disease is present.
00:12
So if we denote s as the event of being a sufferer and n s as the event of being non -suffer and p be the event of getting positive result.
00:36
Then we can denote this 0 .95 as probability of p given yes when it is given that the person is suffered the probability of getting positive result is equal to 0 .95 similarly we can denote p of p given n s as 0 .15 when the selected person is a non -sufferer, the probability of getting a positive result is equal to 0 .15.
01:15
Also, it is given that 5 percentage of population has the disease.
01:20
It means that out of 100 people, there are 5 people who have that particular disease.
01:27
So it can be denoted by p of s.
01:30
So, p of s is equal to 0 .05.
01:35
Now understand that we are as to find the probability of gene having the disease where it is given that his test result is positive.
01:54
So what we can say is we want the probability of yes given p.
02:03
When it is given that the test result is positive, we need to find the probability of gene actually being a sufferer.
02:10
So the required probability p of s given p is given by the formula.
02:17
P of s times p of p given s divided by p of p of p.
02:25
We know the value of p of s...