00:01
First, we need a balanced chemical reaction.
00:02
I know that it's asked in part b, but i'm going to provide it here at front.
00:07
Arsenic acid has three hydrogen, so it's going to require three moles of sodium hydroxide for complete neutralization.
00:17
If we have 50 milliliters that we want to prepare of sodium hydroxide at a 0 .454 molar concentration, we'll convert the 50 milliliters into liters, then use the molarity to convert the liters into 1 ,000.
00:32
Moles of sodium hydroxide that we need will then multiply by the molar mass of sodium hydroxide to get 9 .08 grams of sodium hydroxide that's required.
00:44
For part b, the equation is as shown above.
00:48
For part c, to calculate the molarity of the 25 mil liter arsenic acid solution, we need to know the moles of arsenic acid and we need to know the volume.
00:58
The volumes provided at 25 mil liters to calculate the moles, we'll take the volume difference of sodium hydroxide in mill liters, convert that into liters, then use the molarity of sodium hydroxide to figure out the moles of sodium hydroxide...