Question

A titration experiment required 25.88 mL of NaOH, which had a concentration of 0.125 M, to reach the endpoint when titrating 15.00 mL of an HCl sample with an unknown concentration. What is the concentration of the HCl solution in molarity? HCl(aq)+NaOH?NaCl(aq)+H2O(l)

          A titration experiment required 25.88 mL of NaOH, which had a concentration of 0.125 M, to reach the endpoint when titrating 15.00 mL of an HCl sample with an unknown concentration. What is the concentration of the HCl solution in molarity?

HCl(aq)+NaOH?NaCl(aq)+H2O(l)

A titration experiment required 25.88 mL of NaOH, which had a concentration of 0.125 M, to reach the endpoint when titrating 15.00 mL of an HCl sample with an unknown concentration. What is the concentration of the HCl solution in molarity?

HCl(aq)+NaOH?NaCl(aq)+H2O(l)

Added by Janet G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ashley Brady

05/31/2022

Step 1

Given: Volume of NaOH = 25.88 mL = 0.02588 L Concentration of NaOH = 0.125 M Number of moles of NaOH = concentration x volume Number of moles of NaOH = 0.125 mol/L x 0.02588 L Number of moles of NaOH = 0.003235 mol Show more…

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A titration experiment required 25.88 mL of NaOH, which had a concentration of 0.125 M, to reach the endpoint when titrating 15.00 mL of an HCl sample with an unknown concentration. What is the concentration of the HCl solution in molarity? HCl(aq) + NaOH → NaCl(aq) + H2O(l)