A train travels along a set of tracks according to the function s(t) = t/3 - 4t ^ 2 + 15t - 2 fort t >= 0 where t measured in seconds and sis measured in meters. On what interval(s) is the train moving to the left?
Added by Clifford R.
Step 1
\[ \frac{ds}{dt} = \frac{1}{3} - 8t + 15 \] Show more…
Show all steps
Close
Your feedback will help us improve your experience
Shannon K and 78 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A train travels along a set of tracks according to the function s(t) = t^3/3 - 4t^2 + 12t + 3, where t is measured in seconds and s is measured in meters. On what interval(s) is the train moving to the left?
Adi S.
A train travels along a set of tracks according to the function s(t) = 2t^3 / 3 - 8t^2 + 30t + 1 where t is measured in seconds and s is measured in meters. On what interval(s) is the train moving to the left? (Enter your answer in interval notation. If entering more than one interval write the intervals as a union.)
Andrew N.
A train is traveling down a straight track at $20.0 \mathrm{~m} / \mathrm{s}$ when the engineer applies the brakes. This results in an acceleration of $-1.00 \mathrm{~m} / \mathrm{s}^{2}$ as long as the train is in motion. How far does the train move during a $40.0-\mathrm{s}$ time interval starting at the instant the brakes are applied?
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD