A triangle has sides a = 2 and b = 3 and angle C = 60 (as in Exercise 59). Find the sine of angle B using the law of sines.
Added by Christina G.
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The law of sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is the same for all three sides. So, we have: $$\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}$$ Show more…
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(a) A triangle has sides a = 2 and b = 3 and angle C = 60. Find i. the length of side c. ii. Find the sine of angle B using sine rules. (b) If we have a triangle which has one of its side c = 2 and angles A = π/4 and B = π/3. Workout the length a of the side opposite A.
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