Question

A uniform soda can of mass $0.140 \mathrm{~kg}$ is $12.0 \mathrm{~cm}$ tall and filled with $0.354 \mathrm{~kg}$ of soda (Fig. $9-41$ ). Then small holes are drilled in the top and bottom (with negligible loss of metal) to drain the soda. What is the height $h$ of the com of the can and contents (a) initially and (b) after the can loses all the soda? (c) What happens to $h$ as the soda drains out? (d) If $x$ is the height of the remaining soda at any given instant, find $x$ when the com rcaches its lowest point.

          A uniform soda can of mass $0.140 \mathrm{~kg}$ is $12.0 \mathrm{~cm}$ tall and filled with $0.354 \mathrm{~kg}$ of soda (Fig. $9-41$ ). Then small holes are drilled in the top and bottom (with negligible loss of metal) to drain the soda. What is the height $h$ of the com of the can and contents (a) initially and (b) after the can loses all the soda?
(c) What happens to $h$ as the soda drains out? (d) If $x$ is the height of the remaining soda at any given instant, find $x$ when the com rcaches its lowest point.

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Added by Frederick B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

06/29/2022

Step 1

140 \, \text{kg}\), \(m_s = 0.354 \, \text{kg}\), and \(h = 12.0 \, \text{cm}\). \[h_{\text{cm}} = \frac{0.140 \cdot 12.0}{2} + \frac{0.354 \cdot 12.0}{2} = 6.0 \, \text{cm}\] Show more…

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A uniform soda can of mass $0.140 \mathrm{~kg}$ is $12.0 \mathrm{~cm}$ tall and filled with $0.354 \mathrm{~kg}$ of soda (Fig. $9-41$ ). Then small holes are drilled in the top and bottom (with negligible loss of metal) to drain the soda. What is the height $h$ of the com of the can and contents (a) initially and (b) after the can loses all the soda? (c) What happens to $h$ as the soda drains out? (d) If $x$ is the height of the remaining soda at any given instant, find $x$ when the com rcaches its lowest point.

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