00:01
What is the height h of the center of mass of the can and contents initially? so we're looking at part a, and then b after it loses all the soda.
00:14
So initially, our height for our center of mass is equal to the mass of our can times height over 2, plus the mass of the soda times height over 2, divided by the mass of the can plus the mass of a soda.
00:29
And so this turns out to be just h over 2.
00:32
So we divide our 11 .5 centimeters by 2 to get 5 .75 centimeters.
00:44
Now for b, after loses all the soda, then our h center of mass is just going to be h over 2 again, which is still 5 .75 centimeters.
00:57
For c, we'd like to find what happens to h as the soda drains out.
01:02
So as our soda drains out, our center of mass of our can and our soda are going to be slowly changing.
01:09
So we can have a new expression, mass of our soda prime, equal to mass over soda times x over h.
01:17
And we also have height of our soda prime equal to x over 2...