A varying current in a coil changes from 10 A to 0 in 0.5 sec , if the average emf induced in th

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Ankur S · Answer

Hello students in this question we have given a coil whose current changes from i1 equals to 10

Varsha Aggarwal · Answer

So we know E equals L, D -I by D -T, L equal E, D -T by D -I. So E is 8 into 0 .05 by 2, equal 4

Ajay Singhal · Answer

Hello students in this question we have the current which is changing from plus 2 ampere to minu

Ankur S · Answer

So in this question we have given that when current changes from i1 equals to plus 2 ampere to i

Narayan Hari · Answer

In this problem, L is equal to 5phe, I is equal to 1 ampere, changing to 2 ampere, changing to 2

A varying current in a coil changes from 10 A to 0 in 0.5 sec , if the average emf induced in the coil is 220 V , the self-inductance of the coil equals \( \qquad \) (A) 5 H (B) 6 H (C) 11 H (D) 12 H