A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. How long does he have to get out of the way if the shot was released at a height of 2.20 m, and he is 1.80 m tall?
Added by Lisa C.
Step 1
80 m (the height of the shot putter). Given: Initial velocity (u) = 11.0 m/s Initial height (h) = 2.20 m Final height (h') = 1.80 m Acceleration due to gravity (g) = -9.81 m/s^2 (negative because it acts downwards) Use the kinematic equation: h' = h + ut + Show more…
Show all steps
Your feedback will help us improve your experience
Ivan Kochetkov and 74 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of $11.0 \mathrm{m} / \mathrm{s}$. How long a time does he have to get out of the way if the shot was released at a height of $2.20 \mathrm{m}$ and he is $1.80 \mathrm{m}$ tall?
Assume air resistance is negligible unless otherwise stated. A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of $11.0 \mathrm{m} / \mathrm{s}$. How long does he have to get out of the way if the shot was released at a height of $2.20 \mathrm{m},$ and he is $1.80 \mathrm{m}$ tall?
A shot-putter throws the shot with an initial speed of 12.2 $\mathrm{m} / \mathrm{s}$ from a height of 5.15 $\mathrm{ft}$ above the ground. What is the range of the shot if the launch angle is (a) $20.0^{\circ},$ (b) $30.0^{\circ},$ or $(\mathrm{c}) 40.0^{\circ} ?$
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD