a what is the magnitude of the net magnetic field in t at the center of the two loops b what is

Step 1: Calculate the magnetic field at the center of each loop using the formula for the magnet

A what is the magnitude of the net magnetic field in t at...

(a) What is the magnitude of the net magnetic field (in μT) at the center of the two loops? (b) What is the direction of the net magnetic field at the center of the two loops? - out of the screen - into the screen - toward the top of the screen - toward the bottom of the screen (c) Let r₁ remain fixed at 12.0 cm and let r₂ be a variable. Determine the value of r₂ (in cm) such that the net field at the center of the loops is zero.

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Transcript

00:01 Hi, here in this given problem, there are two concentric current carrying loops, the smaller one and the bigger one.

00:14 Concentric and go planar, both of them.

00:18 The radius of the bigger one, this is r1 and that of the smaller one.

00:27 This is r2.

00:29 Current passing through the smaller loop.

00:31 This is i2, counterclockwise and that passing through the outer loop, bigger loop, this is i1.

00:40 Clockwise.

00:42 Values of the current current is, current i1 is 5 .30 amper.

00:51 Current i2 is 2 .30 amper.

00:56 Radius r1 is equal to 12 .0.

01:01 Centimeter radius r2 is 8 .70 centimeter.

01:09 Now in the first part of the problem we have to find net magnetic field at the center of this center the common center of both of the loops circular loops.

01:22 So first of all there is b1 magnetic field due to the outer loop and as the current is clockwise so clockwise means it will behave like a south pole and due to the south polarity, the current will be entering, sorry, the magnetic field will be entering into the loop.

01:42 So b1 will be given by mu not into i1 by 2 r1 and it will be into the page.

01:56 So it will be taken as negative as per the given convention.

02:00 And b2 is due to the smaller coil.

02:05 The direction of current here is counterclockwise...

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