Question

A wire 50.0 $\mathrm{cm}$ long carries a 0.500 A current in the positive direction of an $x$ axis through a magnetic field $\vec{B}=$ $(3.00 \mathrm{mT}) \hat{\mathrm{j}}+(10.0 \mathrm{mi} 1) \hat{\mathrm{k}}$ . In unit-vector notation, what is the magnetic force on the wire?

Name: A wire 50.0 cm long carries a 0.500 A current in the positive direction of an x axis through a magnetic field B⃗= (3.00 mT) ĵ+(10.0 mi 1) k̂ . In unit-vector notation, what is the magnetic force on the wire?
Uploaded: 2021-11-18T16:23:58-08:00
Duration: 1 min 56 s
Channel: Ankur S
Description: A wire 50.0 cm long carries a 0.500 A current in the positive direction of an x axis through a magnetic field B⃗= (3.00 mT) ĵ+(10.0 mi 1) k̂ . In unit-vector notation, what is the magnetic force on the wire?

          A wire 50.0 $\mathrm{cm}$ long carries a 0.500 A current in the positive direction of an $x$ axis through a magnetic field $\vec{B}=$ $(3.00 \mathrm{mT}) \hat{\mathrm{j}}+(10.0 \mathrm{mi} 1) \hat{\mathrm{k}}$ . In unit-vector notation, what is the magnetic force on the wire?

Added by Marina B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ankur S

11/18/2021

Step 1

Given: Current vector, $I = 0.500 \, A$ in the positive x-direction Length vector, $L = 0.500 \, m$ in the positive x-direction The cross product of $I$ and $L$ is given by $I \times L = I \cdot L \cdot \sin(\theta)$, where $\theta$ is the angle Show more…

Show all steps

Thanks for your feedback!

A wire 50.0 $\mathrm{cm}$ long carries a 0.500 A current in the positive direction of an $x$ axis through a magnetic field $\vec{B}=$ $(3.00 \mathrm{mT}) \hat{\mathrm{j}}+(10.0 \mathrm{mi} 1) \hat{\mathrm{k}}$ . In unit-vector notation, what is the magnetic force on the wire?