Question

A wire having a mass per unit length of 0.540 g/cm carries a 1.60-A current horizontally to the south. (a) What is the direction of the minimum magnetic field needed to lift this wire vertically upward? northward eastward (correct) southward westward (b) What is the magnitude of the minimum magnetic field needed to lift this wire vertically upward? __________ T

Name: a wire having a mass per unit length of 0540 gcm carries a 160 a current horizontally to the south a what is the direction of the minimum magnetic field needed to lift this wire vertically u 28778
Uploaded: 2022-05-10T11:50:13-08:00
Duration: 1 min 48 s
Channel: Shaiju T
Description: a wire having a mass per unit length of 0540 gcm carries a 160 a current horizontally to the south a what is the direction of the minimum magnetic field needed to lift this wire vertically u 28778

          A wire having a mass per unit length of 0.540 g/cm
carries a 1.60-A current horizontally to the south.
(a) What is the direction of the minimum magnetic field needed
to lift this wire vertically upward?
northward
eastward    (correct)
southward
westward
(b) What is the magnitude of the minimum magnetic field needed to
lift this wire vertically upward?
__________ T

Added by Nicole S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

05/10/2022

Step 1

Given: Mass per unit length (M/L) = 0.540 g/cm = 0.054 kg/m Current (I) = 1.60 A Acceleration due to gravity (g) = 9.8 m/s^2 Magnetic force (F) = M * g = 0.054 * 9.8 = 0.5292 N Show more…

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A wire having a mass per unit length of 0.540 g/cm carries a 1.60-A current horizontally to the south. (a) What is the direction of the minimum magnetic field needed to lift this wire vertically upward? northward eastward (correct) southward westward (b) What is the magnitude of the minimum magnetic field needed to lift this wire vertically upward? __________ T