Question

A wire is composed of aluminum with length ℓ1 = 0.140 m and mass per unit length μ1 = 1.47 g/m joined to a steel section with length ℓ2 = 0.880 m and mass per unit length μ2 = 0.451 g/m. This composite wire is fixed at both ends and held at a uniform tension of 136 N. 1) Find the lowest frequency standing wave that can exist on this wire, assuming there is a node at the joint between aluminum and steel. 2) How many nodes (including the two at the ends) does this standing wave possess?

          A wire is composed of aluminum with length ℓ1 = 0.140 m and mass per unit length μ1 = 1.47 g/m joined to a steel section with length ℓ2 = 0.880 m and mass per unit length μ2 = 0.451 g/m. This composite wire is fixed at both ends and held at a uniform tension of 136 N.

1) Find the lowest frequency standing wave that can exist on this wire, assuming there is a node at the joint between aluminum and steel.
2) How many nodes (including the two at the ends) does this standing wave possess?

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Added by Elizabeth D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/01/2022

Step 1

Given: - Length of aluminum section, \( \ell_1 = 0.140 \, m \) - Mass per unit length of aluminum section, \( \mu_1 = 1.47 \, g/m = 1.47 \times 10^{-3} \, kg/m \) - Length of steel section, \( \ell_2 = 0.880 \, m \) - Mass per unit length of steel section, \( Show more…

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A wire is composed of aluminum with length ℓ1 = 0.140 m and mass per unit length μ1 = 1.47 g/m joined to a steel section with length ℓ2 = 0.880 m and mass per unit length μ2 = 0.451 g/m. This composite wire is fixed at both ends and held at a uniform tension of 136 N. 1) Find the lowest frequency standing wave that can exist on this wire, assuming there is a node at the joint between aluminum and steel. 2) How many nodes (including the two at the ends) does this standing wave possess?

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