The total momentum before the woman jumps off is given by:
\(m_{\text{woman}} \times v_{\text{woman}} + m_{\text{canoe}} \times v_{\text{canoe}} = 40 \, \text{kg} \times 1.5 \, \text{m/s} + 59 \, \text{kg} \times 0 = 60 \, \text{kg} \cdot \text{m/s}\)
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