1. (a) Write down the equation for the capacitance of a...

1. (a) Write down the equation for the capacitance of a parallel plate capacitor with dielectric material inside. Identify the meaning of each symbol in the equation. C = ??A/d (b) A parallel plate capacitor has plates with dimensions 1.00 cm × 40.0 cm. The separation between plates is 0.200 m. If the capacitor filled with Mica with dielectric constant of 7.00, calculate the capacitance. C = (8.85 × 10?¹²)(7)(0.4)(0.01) / (0.2) C = 1.239 × 10?¹² = 1.24 × 10?¹² F (c) If the plates were connected to 12.0 V battery, calculate the magnitude of the charge on a plate. Q = CV Q = (1.24 × 10?¹²)(12) Q = 1.488 × 10?¹¹ = 1.49 × 10?¹¹ C (d) Calculate the total energy stored in the capacitor when connected to 12.0 V battery. PE = 1/2 CV² PE = 1/2 (1.24 × 10?¹²)(12)² = 8.928 × 10?¹¹ = 8.93 × 10?¹¹ J (e) If you increase the voltage between the capacitor what would happen to the following quantities. Capacitance - Reason: Energy stored - Reason:

Transcript

00:01 All right, we're going to take a look at this parallel plate capacitor.

00:06 And part a, we're just going to really look at the equation and what each part is.

00:13 Okay, so our capacitance is kappa.

00:16 This kappa is the dielectric constant.

00:19 So kappa is the die electric constant.

00:23 So if i don't have just air or i'm not in a vacuum, then when i add a material that depending on the material, i can get more capacitance depending on the material i put between the plates.

00:35 So that kappa is that kind of multiplier of permittivity of free space.

00:41 So this next one, efsa and not, that's a permittivity of free space.

00:51 So if i have air and air, the kappa is about one.

00:54 So if i'm in air or vacuum, then that helps me, that number gets helps me get basically the kepasans value.

01:03 Then i have the physical area of the plate.

01:06 So this a, this a is the actual area of the plate.

01:10 So the a then stands for area of the plates.

01:13 So a is area of one of the plates.

01:22 And finally, d is the distance between the plates.

01:24 So we have this distance here.

01:26 So if i were to draw, it would be this distance here, the distance between the plates.

01:31 So d is distance between the plates.

01:40 Okay, so that's how we can create a capacitor by putting in a certain material and they can place a certain size and so on.

01:50 Okay, so now we're given a specific example, and let's take a look at the example.

01:56 I'm just going to draw a line so we can kind of see what we're doing.

02:01 Okay, so the example is that the area is 0 .01 meters by 0 .4 meters, which becomes 0 .4 meters, which becomes 0 .0 .4 .4 meters, which becomes 0.

02:12 0 .004 meters.

02:15 However, i have to say that's the bizarrest ever capacitor because that's really skinny.

02:22 It's like one centimeter times 40 centimeters.

02:24 So it's like super long.

02:26 That's a really bizarre capacitor.

02:29 And then not only that, the distance they gave us is 0 .2 meters.

02:35 It should d should be really, really small.

02:38 Those parallel plates should be really close to each other.

02:41 And yet they made it relative like far apart, right? these plates are kind of far apart.

02:46 It's supposed to be kind of, supposed to be 3d.

02:51 Wow.

02:52 Okay.

02:52 So anyway, there's something funny with the problem because you get all sorts of edge effects and the capacitance equation wouldn't work very well for these dimensions, but let's just go with it and maybe they just have an algorithm, which, you know, gives weird numbers.

03:08 Okay.

03:09 So this is micah, so we know, our kappa is seven.

03:13 All right.

03:14 So first thing we're going to do is we're just going to plug in to our capacity equation, plug in all the parts.

03:21 Here's our equation.

03:22 So we're going to plug in all the parts.

03:24 Our kappa is 7.

03:26 Our epsom sum nod is 8 .85 times 10 to minus 12...

Question

Please give Ace some feedback