00:01
Hello students, let's have a look on the question.
00:02
For the given circuit, we have to find the many many things here, almost 5 to 6 things.
00:06
So, first of all we have to find the value of the alpha.
00:09
So, moving on the value of the alpha here.
00:12
So, what is the formula for the alpha? alpha is a formula or simply r by 2l, where r is the resistance that is given to us 4 kilo ohm and n is the inductance that is given to us 10 milli henry.
00:25
So, simply put the values here.
00:27
So, we will get simply l is equal r is equal to 4, n it is equal to 2 into simply we can say here 10 milli henry 10 raise to power minus 3.
00:38
So, after solving this value, i will get simply here the alpha is equal to alpha is equal to 0 .2 m.
00:46
This is the value of the alpha.
00:48
Now, moving on the second question here, we have to find the resonant frequency and there is a formula of 1 by root lc and also we have given both the values.
00:59
So, i will put just a value of the l is 10 m and what is the value of this is 2 .5 n and when we solve this value, i will get that 0 .2 m radian sorry radian per second.
01:14
This is the value of the omega naught for this question.
01:17
Moving on the question number 3, we have to find here the differential equation.
01:21
So, just writing here the differential equation for this loop.
01:25
So, i will get minus v s plus r i t and plus l plus l plus l again d i t by d t plus v t equal to 0.
01:42
So, finally, i will get this equation as v t equal to 12 minus 4 k, then i t, then minus 10 m, then d i t by d t...