00:01
Hello student, to solve the given question, let us write the formula for absolute pressure p equals p .0, that is atmospheric pressure plus ro gh.
00:10
So using this relation, we can solve the given question.
00:14
Firstly, for part a, at the bottom of container, the pressure p2 will be equal to p1 plus row w, that is density of water, gh2.
00:26
Now here we can use the given relation in the formula and plug in here we will get p .0 plus row gh1 plus row w gh2 equals the absolute pressure.
00:42
Now p2 here is the absolute pressure.
00:45
So according to the values given in the statement, we can find the density of the liquid or fluid as plug in the values 1 .049 into 10 .5 .5.
00:59
That is absolute pressure equals atmospheric pressure is 1 .013 into 10 to power 5 plus density multiply by 9 .8 into h1 that is 0 .349 meters plus the last term will be 1 into 1010 to par 3 density of water into 9 .8 multiply by h2 0 .215 meters.
01:27
So after this calculation we get the final answer for the density for part a equals 436 .5 kilogram per meter cube.
01:42
Next, for part b to calculate the diameter, we can use the relation for mass that is equal to density multiply by volume.
01:53
So using this relation we can calculate part b according to which let us first write the force equation.
02:02
M1g plus f equals m2g...