00:02
In the given question, taste bud volume was given as 2 x 104 mu m3.
00:15
The taste buds are found to be spherical in nature.
00:20
These statements were given in the question.
00:22
We have to find the diameter of the taste bud.
00:26
So, v is equal to 2 x 104 mu m3.
00:31
We have to know what is v.
00:34
For spherical, the value formula is going to be 4 x 3 pi r3.
00:41
This is the formula for the value.
00:44
So, we are going to equate it.
00:47
We are going to substitute 4 x 3 pi r3 is equal to 2 x 104 mu m3.
00:55
We have to know the r.
00:57
So, r3 is equal to 2 x 3 x 104 mu m3 divided by 4 pi.
01:07
So, r3 we have to substitute further.
01:11
That is equal to 6 x 104 mu m3 divided by 4.
01:18
Where we know pi is equal to 3 .14.
01:22
3 .14 is the formula for the pi.
01:25
We are going to substitute it.
01:29
When we substitute it, we will further simplify r3 is going to be 4 x 777 mu m3.
01:40
It is a cube.
01:41
So, we have to make the cube root.
01:43
So, that r is going to be 4 x 777 mu m3 cube root.
01:50
So, cube root meter cube is going to be cancelled.
01:54
Then we will get r is equal to 16 .8 mu m.
01:59
It is going to be the radius of the taste bud.
02:04
We have to find the diameter.
02:06
So, radius is going to be twice the radius is going to be a diameter.
02:11
So, we will find the diameter through radius d is equal to 2 x 16 .8 mu m.
02:18
When we apply it, we will get 33 .6 mu m.
02:25
Well, we can substitute mu as 10 power minus 6.
02:29
33 .6 x 10 power minus 6 m.
02:35
And also get divided by 110 and get 3 .36 x 10 power minus 5 m.
02:44
Thus, the diameter of the taste bud was found to be 3 .36 x 10 power minus 5 m.
02:52
We have found the first question answer, the diameter of the taste bud.
02:58
Now, we are going to see the time taken for the sodium ions to diffuse across the taste bud.
03:07
We have to find it.
03:09
So, the formula for this is time is equal to x square divided by 2 d.
03:16
Here, x is found to be the diameter of the taste bud, which is 3 .36 x 10 power minus 5 m.
03:29
Then, d is going to be a diffusion coefficient of sodium ions.
03:36
The diffusion coefficient of sodium ions is going to be 1 .3 x 10 power minus 9 m2 per second.
03:45
So, now we have to substitute it here.
03:48
T is equal to 3 .36 x 10 power minus 5 m the whole square divided by 2 x 1 .3 x 10 power minus 9 m2 per second.
04:05
Now, we will simplify it.
04:08
T is equal to 11 .29 x 10 power 9 second divided by 2 .6 x 10 power 10 m2 per second.
04:20
Here, the second 1 by s is bent upwards.
04:23
So, we got s on the fraction.
04:26
When we further simplify it, divide 10 power 9 x 10 power 10 m2 per second...