00:01
Okay, so we're solving a fairfield problem.
00:04
So the first thing i do is, it's no representation of fairfield on the left.
00:09
I've got a circle with a ring, and i've got horizontal line representing the ground, and you recall that in the bottom of fairsville is 1 .12 meters of ground.
00:22
Now, if you assume that you start in that car, that's right bottom of the field, then we can represent that as the order to areas v -row 2 at times 0 before i started you were already 1 .45.
00:37
Right now it says it makes one rotation of its 10 well if you take 10 divided by 4 you get 2 .5 and what that means is once the ferris will reach it will take you two and a half seconds to get here another two and a half seconds to get me of six and another two and a half second for a total of ten seconds you're back to one point so now i've described zero common one to and ten comma one and i've described why these x coordinates are two point five five and seven point so now what about these wide coordinates well you see the radius goes from here to this point so then when you're at this part of the ride, your height above the ground is 9 .5 plus 1 .2 for 10 .7.
01:47
Then when you get to this point, your height is 1 .2 plus 9 .5 plus 20 .2.
01:59
When you get to this point on the ride, your height is the same as 1 .2 and a half second.
02:05
So now i've got five order pairs around now come over here to the right where the x -axis is high and the y -axis type.
02:16
Zero comma 1 .2, 2 .5, 10 .7, 5, 20 .2, 7 .5, back down to 10 .7, and 10, 0 .2.
02:35
This is what your ride looks like around the water, voucherment of time.
02:40
Now i don't know about you, but this looks like a cosine way upside down.
02:46
Y equals a cosine b times x minus c plus b, where each of these values represent some special.
03:02
A equals for two.
03:05
B is related to the period.
03:10
It's 2 pi divided by the period.
03:16
C is called the phase chip and d is called the vertical shift.
03:29
And so if we look at our function, we should be able to find each one in the values.
03:35
Now, i want you to take a look at how, what order to do this now.
03:40
I've noticed right away that the midline is y equals 10 .7.
03:53
Well, that is automatically the vertical shift line.
03:59
Okay, now the amplitude is the distance from a high point to the midline...