According to the following reaction, how many grams of potassium sulfate are necessary to form 0.592 moles barium sulfate? BaCl2 (aq) + K2SO4 (aq) BaSO4 (s) + 2KCl (aq) grams potassium sulfate
Added by Ashley R.
Step 1
33 g/mol S: 32.06 g/mol O: 4(16.00 g/mol) = 64.00 g/mol Total molar mass = 137.33 + 32.06 + 64.00 = 233.39 g/mol Show more…
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