00:01
So to find the amount of barium sulfate, let us first write the equation for this reaction.
00:12
So we have barium chloride.
00:14
Okay, barium chloride that's going to be b -a -t -l -2 and sodium sulfate reacted with it.
00:22
So that means we have an a2, s -o -4, and it will produce barium sulfate, of course.
00:30
So it's going to be barium sulfate as 04 and then we'll get an acl also okay so you'll write and then let us balance this first as you can see we have one volume in both sides and one is of four in both sides and that means our cl is unbalanced so that means we'll have to write here too so that we have two uh cl and both um sides of the and also for sodium.
01:03
So that means this will be our balance equation.
01:05
We cannot proceed with our calculation for the number of moles and of baso4.
01:11
Okay.
01:13
So we have the mass of sodium sulfate.
01:19
So let's write here 22 .9 grams of an h2 s .04, this is grams, right? and we need this to be converted into moles.
01:28
So we're going to have to multiply the.
01:31
Molar mass of an a2s04 and that's 142...