According to the national health survey, the heights of adult males in the United States are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. What is the probability that an adult male chosen at random is between 66 and 72 inches tall? (Round your answer to three decimal places.) What percentage of the adult male population is more than 6 feet tall? (Round your answer to one decimal place.)
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Given: Mean (μ) = 69 inches Standard Deviation (σ) = 2.8 inches For 66 inches: \( z = \frac{66 - 69}{2.8} = -1.0714 \) For 72 inches: \( z = \frac{72 - 69}{2.8} = 1.0714 \) Show more…
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According to the National Health Survey, the heights of adult males in the United States are normally distributed with mean 69.0 inches and standard deviation 2.8 inches (a) What is the probability that an adult male chosen at random is between 66 and 72 inches tall? (Round your answer to three decimal places.) (b) What percentage of the adult male population is more than 6 feet tall? (Round your answer to one decimal place.) %
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