00:01
Let's discuss this question.
00:03
So, acetylene gas, that is, c2h2 undercose, combust into form carbon dioxide in water when it is used in the oxyacetylene torch for welding.
00:13
So we need to balance the reaction and answer the following.
00:15
Here we have to find two things.
00:17
Firstly, how many grams of water can be formed if 113 grams of acetaline is burned? and secondly, how many grams of acetylene reacts with 1 .10 mole of carbon dioxide are produced? so here for question number a, before that we'll write the equation.
00:34
So here we have c2h2 in gaseous form plus oxygen in gaseous form gives us carbon dioxide in gaseous form plus water in gaseous form.
00:47
So here we can say a, that is, 2 mole acetylene reacts with 5 mole, o2 to produce 4 mole, carbon dioxide and 2 mole water.
01:22
So here we can say molar mass of c2 h4 will be equal to 26 gram per mole.
01:32
So here we can say 113 grams of c2 h2 will be equal to 113 grams 26 grams per mole.
01:44
So this is equal to 4 .34 mole.
01:51
So here we can say therefore 4 .34 mole c2h2 bond to produce 4 .34 mole of h2o.
02:15
So here we can say therefore grams of h2o produced will be equal to 4 .34 moles multiplied by 18 .9.
02:37
Grams mole inverse so here we can say therefore 78 .23 grams of h2o is produced and this is the final answer...