Question

After a precipitation reaction with 0.64M H2SO4 was completed, you centrifuge the sample, dry and weigh it. The ppt is found to weigh 0.114 grams. Based on this mass, what was the original concentration of the unknown Pb(NO3)2 solution in mol/L? Answer to 3 sf. [Pb(NO3)2] =

          After a precipitation reaction with 0.64M H2SO4 was completed, you centrifuge the sample, dry and weigh it. The ppt is found to weigh 0.114 grams. Based on this mass, what was the original concentration of the unknown Pb(NO3)2 solution in mol/L? Answer to 3 sf.
[Pb(NO3)2] =

After a precipitation reaction with 0.64M H2SO4 was completed, you centrifuge the sample, dry and weigh it. The ppt is found to weigh 0.114 grams. Based on this mass, what was the original concentration of the unknown Pb(NO3)2 solution in mol/L? Answer to 3 sf.
[Pb(NO3)2] =

Added by Ricky C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

09/21/2022

Step 1

Given mass of PbSO4 = 0.114 grams Molar mass of PbSO4 = 303.26 g/mol Number of moles = Mass/Molar mass Number of moles = 0.114 g / 303.26 g/mol Number of moles = 0.000376 moles Show more…

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After a precipitation reaction with 0.64M H2SO4 was completed, you centrifuge the sample, dry and weigh it. The ppt is found to weigh 0.114 grams. Based on this mass, what was the original concentration of the unknown Pb(NO3)2 solution in mol/L? Answer to 3 sf. [Pb(NO3)2] =