00:01
Hello, since the concentration of pb -n03 holt2 solution is definitely low below 1 .0m, it is safe to assume a concentration of 1 .0 -0 -m for calculation, this will ensure that the reaction is complete, and h -2 -s -o -4 acts as a limiting reagent.
00:14
So, also, pb, no3, whole -twice, is equal to, in the solution reactor, it is equal to molarity multiplied by volume in later.
00:21
So when we put the values into this, so this would be equal to 1 .0m multiplied by 1 .0 many data multiplied by 1 data divided by 1000 m m.
00:31
So this is equal to 0 .01 mole.
00:34
Now the reaction which is pb no 3 hold twice aque plus h2 so4 aquas gets converted into pb so4 solid, pb so4 this is in solid form plus 2 hno3 and this is in equest form.
00:49
So most of h2, so4 is equal to most of pb no3 or we can say 0 .62m multiplied by volume and later is equal to 0 .01, 0 .001 we would say, mole.
01:05
So volume is equal to 0 .001 mold divided by 0 .62, mold divided by liter.
01:16
So this is equal to 1 .61 multiplied by 10 to 0 .3 to minus 3 liter.
01:20
So volume of h2 as a fourth reacted would be equal to 1 .61 multiplied by 10 to power minus 3, multiplied by 1 ,000 m l divided by liter.
01:29
So, this is equal to 1 .61 is the answer...