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after going down the ramp the kid on the skatboard coasts to a stop along the flat ground they roll 30m before they come to a stop what is the averge force of friction doing the work to stop them express as a positive if it is in the direction 

          after going down the ramp the kid on the skatboard coasts to a stop along the flat ground they roll 30m before they come to a stop what is the averge force of friction doing the work to stop them express as a positive if it is in the direction
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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after going down the ramp the kid on the skatboard coasts to a stop along the flat ground they roll 30m before they come to a stop what is the averge force of friction doing the work to stop them express as a positive if it is in the direction
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Transcript

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00:01 In this question we have mass of child is equal to 41 kg and initial velocity is 1 .8 meter per second and according to question final velocity is 0 meter per second and time difference delta t is equal to 0 .7 second so we know that impulse i is equal to change in momentum means initial final momentum minus initial momentum so formula of momentum is mv so m and into well final velocity minus m into initial velocity and here final velocity is zero so i is equal to m into initial velocity vi put the values then we get minus 41 into 1.
01:04 Is equal so impulse is equal to 73 minus 73 .8 newton into meter and we know that i impulse is equal to force into time interval so force is equal to impulse divide by time interval here impulse is 73 .8 and time interval is 0 .7 so after calculation average force is equal to 105 .42 newton...
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