Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 45.0 cm . The explorer finds that the pendulum completes 103 full swing cycles in a time of 129 s . What is the magnitude of the gravitational acceleration on this planet?

Name: after landing on an unfamiliar planet a space explorer constructs a simple pendulum of length 450 cm the explorer finds that the pendulum completes 103 full swing cycles in a time of 129 s w 78298
Uploaded: 2022-03-22T04:44:26-08:00
Duration: 1 min 23 s
Channel: Ankur S
Description: after landing on an unfamiliar planet a space explorer constructs a simple pendulum of length 450 cm the explorer finds that the pendulum completes 103 full swing cycles in a time of 129 s w 78298

          After landing on an unfamiliar planet, a space explorer
constructs a simple pendulum of length 45.0 cm . The explorer finds
that the pendulum completes 103 full swing cycles in a time of 129
s .
What is the magnitude of the gravitational acceleration on this
planet?

Added by Denise L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ankur S

03/22/2022

Step 1

Given: Length of pendulum, L = 45.0 cm = 0.45 m Number of swing cycles, n = 103 Time taken for n swing cycles, t = 129 s Time period, T = t / n T = 129 s / 103 T = 1.252 s Show more…

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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 45.0 cm . The explorer finds that the pendulum completes 103 full swing cycles in a time of 129 s . What is the magnitude of the gravitational acceleration on this planet?