After the skier on the $37^{\circ}$ hill in Example Problem 6 had been moving for $5.0 \mathrm{s}$, the friction of the snow suddenly increased and made the net force on the skier zero. What is the new coefficient of friction?
Added by Natalie B.
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This can be represented as $MG \sin \theta = \mu_k \cdot MG \cos \theta$, where $\mu_k$ is the coefficient of kinetic friction. Show more…
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