00:01
In the right answer this question, let's talk about in haytans.
00:03
It says, consider a true breeding plant that is like this, homocygous dominant for three genes, okay? crossed with another true breeding plant that is homocygous recessive for the three genes.
00:15
And it says, whose resulting offspring are heterocygous for all the genes, okay? this is going to be the f1 progeny.
00:24
So it says, if you cross the f1 where independent assortment is operational, one proportion of the offspring would be expected to contain two operas cases.
00:34
So you want this cross practically.
00:38
This with another organism with the same unit type.
00:42
So in this case, you're going to do three monohyroidine squares in these heterocygous with this heterocyg with this heterocyg.
00:49
That same for the b -gene and that same for the c gene.
00:52
So let's make three monohymonohympanidasequets here.
00:58
You have homocygumonidylylacinate, heterocygose, hydrocygos and homozygous excessive.
01:02
For the v, cross you're about to have homozygous dominant, heterocygoyles, heterocygous and homozygose and then for the c cross you're going to have homozygous domine, hydrocygos, hydrocygos, and homozygous recessive.
01:19
So these are your three panels squares.
01:22
And according to this, it says, the proportion of the offspring that would be expected to continue two applications.
01:29
It means you want either this, okay, or this, or this, okay? so you have three possibilities, only three possibilities here.
01:45
So let's do some math here.
01:50
You want to have here, you want the dominant a.
01:52
You have four possibilities here.
01:54
And all possibilities, three are dominant phenotypes.
01:57
So you have here, for the a, you have three quarters.
02:00
You have to multiply this by the proportion to get a dominant b...