00:01
Hi, in this question we need to find out the correct option regarding the carriers in the population.
00:13
So according to the hard, even by ecliprium, the alleleicine genotype frequency in a population remains constant under the absence of the factor that are responsible for evolution.
00:30
So it states that the sum of all the genotypic frequencies that can be represented as the binomial expansion of the square of the sum of p and q.
00:43
So we can say that the p plus q whole square is equal to p square plus q square plus 2 pq is equal to 1.
00:54
Here, p represents the frequency of the dominant allele, whereas the p square represents the frequency of the homozygous dominant, and the q1 is the frequency of the recessive alien, whereas the q square is the frequency of the homozygous, decisive, and the q1 is the frequency of the homozygous recessive, individual and 2 pq is showing the frequency of the heterozygoth, heterozygous, decessive individual.
01:44
So according to the equation, we know that p plus q is equal to 1.
01:51
We have p plus 0 .16 is equal to 1.
01:58
P is equal to 1...