00:01
Hi, so to solve for this, let's write first the balance equation for this reaction.
00:05
If we have aluminum reacting with magnesium chloride, that's mgcl2, this will form aluminum chloride alcl3 and magnesium.
00:18
So to balance this, we'll write 3 here and then 2 in here.
00:24
We have to write 2 and 3 in here.
00:28
Now this is the balance equation for this reaction.
00:30
We have to determine first the limiting reactant.
00:33
We'll convert the given mass of reactants to moles.
00:36
We'll start with aluminum.
00:38
If we have 8 .60 grams of aluminum, convert this to moles by dividing the molar mass.
00:43
That's 26 .98.
00:45
This is grams and then we have here moles and that means we could cancel grams and we'll get 0 .319.
00:54
This is moles of aluminum and then for magnesium chloride, mgcl2, we have 65 grams of mgcl2.
01:06
Oh, don't need to write it here.
01:11
Then we will divide the molar mass of mgcl2.
01:14
That's 95 .21.
01:17
Cancel this and we'll get 0 .683...