00:01
Hello students, in this question, height of the wall h is equal to 27 meters, width of the wall w is equal to 18 meters, inside temperature is equal to 24 degree celsius and outside temperature is equal to 40 degree celsius.
00:19
First we have to find the building cooling load from the south wall.
00:24
We know that u wall is equal to 1 .4 watt per meter square.
00:30
So the cooling load q will be equal to u wall into h into w into t naught minus t i.
00:44
Substituting we get 1 .4 into 27 into 18 into 40 minus 24.
00:54
So cooling load from the south wall will be equal to 10 .886 kilowatt.
01:04
Next we have to find the cooling load from the window.
01:07
We know that area of the window is equal to 3 into 1 .5.
01:17
This will be equal to 4 .5 meter square.
01:22
Number of window is equal to 2.
01:24
Heat transfer coefficient of the window will be equal to 3 .5 watt per meter square.
01:33
Emissivity of the window mu is equal to 0 .7.
01:37
So the cooling load from the window q is equal to ug into area of the window into mu into n into t naught minus t i.
01:52
Substituting the values we get 3 .5 into 4 .5 into 0 .7 into 2 into 40 minus 24.
02:06
So the cooling load from the glass window q is equal to 352 .8 watts.
02:14
For the third part of the question we have to find the cooling load from lighting.
02:19
Then the lighting load is given as w is equal to 20 watt per meter square.
02:30
Area is given as 27 into 4.
02:33
This will be equal to 108 meter square.
02:37
So the net load wn is equal to 20 into 108.
02:42
This will be equal to 2160 watts.
02:47
Clf is equal to 0 .75...