00:01
Here in this question we have given diameter of stream equals to 1 inch also we have an angle equals to 135 degree.
00:23
Now first we calculate the area of the jet by using the relation that is a equals to pi divided by 4 multiplied by d square, d is the diameter.
00:38
So here on substituting the value we get a equals to pi divided by 4 multiplied by.
00:49
Now we do one thing we just convert the diameter from inch to feet so we can write this as 1 divided by 12 multiplied to the power 2.
01:05
So we can say that a equals to pi divided by 4 multiplied by 1 divided by 12 to the power 2.
01:11
Now on simplifying this in terms of a we get a equals to 5 .45 multiplied by 10 to the power minus 4 feet square.
01:26
Now comes to part a of this question.
01:34
So here first we calculate the mass flow rate using the relation that is m equals to rho multiplied by a multiplied by v.
01:47
Here rho is the density of the fluid, a is the area of the jet and v is the velocity of the jet.
01:52
So now on substituting the value we get m equals to 1 .94 multiplied by 5 .45 multiplied by 10 to the power minus 4 multiplied by 100.
02:13
Now on simplifying we get 1 .058 slug per second.
02:23
Now we determine the torque by using the relation that is t equals to n multiplied by m multiplied by u minus v1 multiplied by 1 minus cos beta.
02:44
Here n is the number of jet, u is the linear velocity of the wheel and beta is the vane fluid deflection angle.
02:52
So now here we substitute 4 for n, 1 .058 slug per second for m, 0 for u, 100 feet per second for v1 and 135 degree for beta...