00:01
Hi, i'm david and i'm here to have you and see your question.
00:03
Now let me pick up your question here.
00:06
In the question here we are going to discuss about the central limit theorem.
00:10
Let me remind to you that here will the n equal to the 30, then the symbol mean x -par, it will be approximately to the normal, in such a way that it will take the x -bar will minus the mean of a standard deviation, divide with square to n, we obtain the standard normal.
00:26
In this question here, we are given the sample size and equal to 100.
00:31
The standard division equal to the 2.
00:33
And from here, once you find the probability that the sum of mean will differ from the proportion mean by no more than 0 .6 inches.
00:42
It means that the absolute of the x bar minus the m will be smaller than the 0 .6.
00:48
Now to find this probability, i will divide both sides by this quantity, sigma over square of n, which is the 2 over square with the 100.
01:00
And if we do it, we will notice that this quantity here turns out to be the z by the formula here.
01:07
And we have the z smaller than equal to 016 divided by 2 times 10 equal to the 3.
01:17
Now to find this probability i need to bring up the z table...