00:01
Hi guys, now in this film an arrow is shot from a height of 1 .75 meters towards a cliff of height, edge.
00:07
It is shot with the velocity of 33 m per second at the angle of 60 degree above the horizon.
00:13
It glanced on the top edge of the cliff 3 .74 second later.
00:20
What is the height edge of the cliff in meters? what is the maximum height reached by the arrow along its trajectory in meters? what is the arrow speed just before it hits the cliff? this is a diagram that we have.
00:35
This is the ground.
00:37
And this is what? this one i can say.
00:40
This is 1 .75 meter.
00:45
A arrow shoot with the angle of what? this is 60 degree.
00:52
This angle is given to a 60 degree.
00:58
We have a cliff which is the height of what? capital of h.
01:08
This one is looked like this this is h we have this cliff is the strikes this one here after time t is equal to 3 .74 meter this is 20 meter per second this is 33 meter per second so 33 cause of 60 that in 16 .5 meter per second vertical component will be what 33 sign of 60 that is 28 .58 meter per second.
02:02
Now we need to find out what is the height of this cliff.
02:05
Now this height is already 1 .75 meter.
02:09
So let's find out this height from this position.
02:12
Height from this one in upper direction after this one i can say, let me say this is h1...