00:01
Centipital acceleration is the acceleration that is directed towards the center of a circular path, and it is solved as the ratio of the square of the speed and the radius.
00:10
These problems were given that with an astronaut that orbits earth from a distance of 400 kilometers above the earth's surface.
00:19
At that point, the acceleration due to gravity is 8 .27 meters per second square.
00:25
Taking the ratios of the earth to be 6 ,400 kilometers, we want to find the earth.
00:31
Speed of the the speed of the satellite where the asteroid is in and for letter b the period of the satellite that means the amount of time it takes for the satellite to make one complete orbit around the earth now we note that the acceleration due to gravity here is also the centripetal acceleration that the satellite experiences as it is drawn towards the earth therefore your ac would be equal to g and from the formula that will be equal to b squared over r now this r here is the total distance from the of the regions of the earth and the distance of the satellite from the surface of the earth so that means your r is going to be equal to 6400 plus 400 and that's equal to 6800 kilometers now in meters, that's just going to be 68 ,000, then multiply by 1000.
01:39
So that means it will be 68000, then add 3 zeros.
01:44
That's basically 6 .8 million meters.
01:48
So rearranging the formula that we have above the software v, we have b is equal to g times r, where your g is 8 .27...