An athlete performing a long jump leaves the ground at a 35.0 ∘∘ angle and lands 7.70 mm away. A) What was the takeoff speed? b) If this speed were increased by just 3.0%, how much longer would the jump be?
Added by Ryan L.
Step 1
70 meters - Angle of takeoff (θ) = 35.0 degrees - Acceleration due to gravity (g) = 9.81 m/s^2 Using the formula for horizontal range: x = (u^2 * sin(2θ)) / g Substitute the given values: 7.70 = (u^2 * sin(70)) / 9.81 Solve for u: u^2 = (7.70 * 9.81) / sin(70) u Show more…
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