Question

An electron in an atom initially has an energy 7.5 eV above the ground state energy. It drops to a state with an energy of 3.2 eV above the ground state energy and emits a photon in the process. The momentum of the photon is: 4. 0 x 10-27 kg.m/s 5. 7 x 10-27 kg.m/s 6. 3 x 10-27 kg.m/s 7. 7 x 10-27 kg.m/s 8. 0 x 10-27 kg.m/s

Name: an electron in an atom initially has an energy 75 ev above the ground state energy it drops to a state with an energy of 32 ev above the ground state energy and emits a photon in the process 72706
Uploaded: 2022-08-08T10:27:47-08:00
Duration: 4 min 43 s
Channel: Adi S
Description: an electron in an atom initially has an energy 75 ev above the ground state energy it drops to a state with an energy of 32 ev above the ground state energy and emits a photon in the process 72706

          An electron in an atom initially has an energy 7.5 eV above the ground state energy. It drops to a state with
an energy of 3.2 eV above the ground state energy and emits a photon in the process. The momentum of the
photon is:
4.  0 x 10-27 kg.m/s
5.  7 x 10-27 kg.m/s
6.  3 x 10-27 kg.m/s
7.  7 x 10-27 kg.m/s
8.  0 x 10-27 kg.m/s

an electron in an atom initially has an energy 75 ev above the ground state energy it drops to a state with an energy of 32 ev above the ground state energy and emits a photon in the process 72706

Added by Jamie C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

08/08/2022

Step 1

The energy difference between the initial and final states is the energy of the photon. $$E_{photon} = E_{initial} - E_{final} = 7.5 eV - 3.2 eV = 4.3 eV$$ Show more…

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An electron in an atom initially has an energy 7.5 eV above the ground state energy. It drops to a state with an energy of 3.2 eV above the ground state energy and emits a photon in the process. The momentum of the photon is: 4. 0 x 10-27 kg.m/s 5. 7 x 10-27 kg.m/s 6. 3 x 10-27 kg.m/s 7. 7 x 10-27 kg.m/s 8. 0 x 10-27 kg.m/s