An electron moves at a velocity of 7.34 x 10^6 m/s in a direction perpendicular to a magnetic field of strength 3.74 T. How much force will the electron experience? Question 8 options: 1.76E-12 N 5.71E-12 N 7.02E-12 N 4.39E-12 N
Added by David M.
Step 1
Since the electron is moving perpendicular to the magnetic field, \( \theta = 90^\circ \) and \( \sin(90^\circ) = 1 \). Show more…
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