1. An elevator containing 3 passengers (with a mass of 72kg 84 kg and 35 kg) has a mass combined of 1030 kg . The cable attached to the elevator exerts an upward force of 9800 N. What is the acceleration with the direction of the elevator at this instance? 9800N - (1030kg)(10) = -500 / 1030kg = -0.49 kg +5/5 Why? 2. An object with a mass of 2.5 kg is placed on a frictionless inclined plane. The angle of the incline is 20 degrees. What is the magnitude of the net force and the normal force? B) Draw a free body diagram sin(20°)(2.5kg) = 2.282° ?
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Step 1: Calculate the total mass of the elevator: Given masses of passengers: 72 kg, 84 kg, 35 kg Total mass of passengers = 72 kg + 84 kg + 35 kg = 191 kg Total mass of elevator = Total mass of passengers + Mass of elevator = 191 kg + 1030 kg = 1221 kg Show more…
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