An Energy Drink company wants to design a new can for their new product. The material to be used for the can is aluminum; and is cylindrical in shape. Design a can that requires the least amount of aluminum to be used; and can contain exactly 16 fluid ounces (28.875 cubic inches). Find the radius and height of the can. radius of the cylinder = $\sqrt[3]{4.6}$ in; height of the cylinder = $\sqrt[3]{9.2}$ in. radius of the cylinder = 3.325 in; height of the cylinder = 1.66. in. radius of the cylinder = 1.21 in; height of the cylinder = 1.66 in. radius of the cylinder = $\sqrt[3]{4.6}$ in; height of the cylinder = $\sqrt[3]{36.8}$ in.
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The volume of a cylinder is given by $V = \pi r^2 h$, where $r$ is the radius and $h$ is the height. The surface area of a cylinder (amount of aluminum) is given by $A = 2\pi r^2 + 2\pi rh$. We are given the volume $V = 28.875$ cubic inches. So, $28.875 = \pi r^2 Show more…
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