00:01
An ice cube at an unknown temperature is added to 25 gram of liquid water at 40 degrees celsius.
00:07
The final temperature of the 29 .3 gram, the colliberated mixture is 21 .5 degrees celsius.
00:18
What was the original temperature of the ice cube? so from there, we know that you want to use the principle of conservation of energy.
00:31
The heat gained by an ice cube as it warm up to 0 degrees celsius melts and the further warm up to 21 .5 degrees celsius must equal the heat lost by the liquid water as it cooled down from 40 to 21.
00:46
So basically, conservation of energy.
00:59
So the warm up energy equals the cool down energy.
01:04
So first of all, calculate the heat lost by liquid water.
01:08
So q of water equals the mass of the water multiplied by the specific heat.
01:24
So the cp has been given is 4 .184 and then multiply by the delta change.
01:33
The mass of the water is 25 gram.
01:38
Cp has been given as 4 .184.
01:43
This is the standard specific heat joual per gram per degree celsius and the change of temperature goes from 40 to 21 .5.
01:58
So then do your math 25 times 4 .184 multiplied by 18 .5.
02:13
That equals 19 35 .1 jewel.
02:25
The next step, calculate the heat absorbed by the ice cube.
02:28
So the qi's equals to the mass.
02:37
We'll just plug in the same equation here.
02:40
Mass multiplied by cp, multiple delta change.
02:44
So that the mass of the ice is a 29.
02:54
39 .3 gram, that's the final weight.
03:01
But you know that an ice cube itself should be added into the 25 gram so that the final mass is 99 .3.
03:15
So the ice cube, its own weight or mass is gonna be 23, 29 .3, final minus 25.
03:23
So this means that the difference is the mass of ice because an ice cube is added into 25 gram of water.
03:38
So this is the final mass.
03:40
So the difference is the mass of ice.
03:42
And then multiply by cp of the ice, we have given the number 2 .06 jou per gram per degree celsius.
03:53
And then the temperature change, its initial temperature is zero.
04:01
And i mean, the final temperature is zero because we know that the ice melt into water at zero degrees of zero degrees celsius, and after that it become water.
04:15
And then we do not know the initial temperature.
04:18
This is what we want to find out.
04:21
So this is the first part of the q.
04:24
This is 4 .3 times 2 .06 times negative or actually this is going to be the difference is the initial temperature...